(4x^2+3x+2)/(2x^2-5x-6)=0

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Solution for (4x^2+3x+2)/(2x^2-5x-6)=0 equation: 



(4x^2+3x+2)/(2x^2-5x-6)=0



Domain of the equation: (2x^2-5x-6)!=0

We move all terms containing x to the left, all other terms to the right

2x^2-5x!=6

x∈R



We multiply all the terms by the denominator


(4x^2+3x+2)=0

We get rid of parentheses

4x^2+3x+2=0

a = 4; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·4·2
Δ = -23
Delta is less than zero, so there is no solution for the equation

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